Container With Most Water

Problem

Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of the line i is at (i, ai) and (i, 0). Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.

Notice that you may not slant the container.

For example:

Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are 
represented by array [1,8,6,2,5,4,8,3,7]. 
In this case, the max area of water 
(blue section) the container can contain is 
49.

Solution

class Solution:
    def maxArea(self, height: List[int]) -> int:
        maxArea = float("-inf")
        i = 0
        j = len(height) - 1
        
        while i < j:
            thisArea = min(height[i], height[j]) * (j-i)
            maxArea = max(maxArea, thisArea)
            if height[i] < height[j]:
                i+=1
            else:
                j-=1
        return maxArea
        
#Two pointer approach: The two pointer approach can 
#be used as we can set both pointers at the end of the
#array and move either pointer forward depending on
#whether ai or aj is the minimum

#Two pointer is the best approach since we need to
#calculate the width between two points